Wednesday, December 2, 2015

How to disable an option already selected in another select?



Question:
I have five HTML selects with different values, but the options have the same text. How do I compare the text options, instead of the values, and disable the the respective option in every other select? For example, if I have:
<select name="options[70]" id="select_70">
  <option value="1" price="0"> test-1 </option>
  <option value="2" price="0"> test-2 </option>
  <option value="3" price="0"> test-3 </option>
</select>
<select name="options[71]" id="select_71">
  <option value="4" price="0"> test-1 </option>
  <option value="5" price="0"> test-2 </option>
  <option value="6" price="0"> test-3 </option>
</select>
<select name="options[72]" id="select_72">
  <option value="7" price="0"> test-1 </option>
  <option value="8" price="0"> test-2 </option>
  <option value="9" price="0"> test-3 </option>
</select>
<select name="options[73]" id="select_73">
  <option value="10" price="0"> test-1 </option>
  <option value="11" price="0"> test-2 </option>
  <option value="12" price="0"> test-3 </option>
</select>
<select name="options[74]" id="select_74">
  <option value="13" price="0"> test-1 </option>
  <option value="14" price="0"> test-2 </option>
  <option value="15" price="0"> test-3 </option>
</select>
Suppose the user selects the option test-1 in the last select. This should disable the corresponding option in the other selects. How can I achieve that?

ANSWERS:
If I understand you properly, this might be it:
var $selects = $('select');
$selects.on('change', function() {
    var $select = $(this), 
        $options = $selects.not($select).find('option'),
        selectedText = $select.children('option:selected').text();
 
    var $optionsToDisable = $options.filter(function() {
        return $(this).text() == selectedText;
    });
 
    $optionsToDisable.prop('disabled', true);
});
 
//to apply initial selection
$selects.eq(0).trigger('change');
jsFiddle: example

Answer2:
A length example
var $selects = $('select');
available = {};
 
// Get the text of options from the dropdown
// and store in a object hash 
$('option', $selects.eq(0)).each(function (i) {
    var val = $.trim($(this).text());
    available[val] = false;
});
 
$selects.change(function () {
    var $this = $(this);
    var selectedVal = $.trim($this.find('option:selected').text());
 
    // set that value to true
    available[selectedVal] = true;
 
    $selects.not(this).each(function () {
        $('option', this).each(function () {
            var optText = $.trim($(this).text()),
                optCheck = available[optText];
 
            $(this).prop('disabled', optCheck );
        });
    });
}).change(); // Trigger once to add options at load of first choice

ANSWER 3:
Expanding on @IgorDymov's answer (credit should go to him), here's probably what I'd do (seefiddle):
var $selects = $('select');
$selects.on('change', function() {
    $("option", $selects).prop("disabled", false);
    $selects.each(function() {
        var $select = $(this), 
            $options = $selects.not($select).find('option'),
            selectedText = $select.children('option:selected').text();
        $options.each(function() {
            if($(this).text() == selectedText) $(this).prop("disabled", true);
        });
    });
});
 
$selects.eq(0).trigger('change');
That way we completely refresh the selections each time a new one is made, which means properties become re-enabled again. You'll notice in the fiddle I reduced the number of selects and increased the number of options so that you don't get trapped in a situation where all options are disabled at the same time, I think that makes most sense.

How to backup and download Database using PHP

< ?php $mysqlUserName = 'databaseusername' ; $mysqlPassword = 'databasepassword' ; $mysqlHostNa...